Advertisement

10.14.2008 at 04:55AM PDT, ID: 23812428
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!
8.9

MFC CString concatenation failure

Asked by muttley3141 in Windows MFC Programming, Microsoft Visual C++

Tags:

If I have a local variable of type CString and then assign to it using the concatenation operator, things work fine:

CString StringFunction1()
{
  CString one;
  one = "ONE";
  return one;
}

CString StringFunction2()
{
  CString two;
  two = "TWO";
  return two;
}

{
  CString x;
  x = StringFunction1() + StringFunction2();
  MessageBox(x);
}

However, if the second function is replaced by a member function of one of my classes,
{
  MyClass myobject;
  CString x;
  x = StringFunction1() + myobject.StringFunction();
  MessageBox(x);
}

then no concatenation happens; the messagebox just shows "ONE".

class MyClass
{
public:
  MyClass();
  CString StringFunction();
};

CString MyClass::StringFunction()
{
  return CString("CSF");
}

I've looked on various google pages, and people keep saying you can't do this because you're returning a pointer to a local variable that no longer exists. Why ? Surely "return" has something like operator= semantics, in that it constructs a copy of whatever it is, in the callER's stack space ?Start Free Trial
[+][-]10.14.2008 at 06:34AM PDT, ID: 22711111

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 07:38AM PDT, ID: 22711683

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 09:48AM PDT, ID: 22713169

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 7-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 10:41AM PDT, ID: 22713749

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 10:43AM PDT, ID: 22713779

View this solution now by starting your 7-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zones: Windows MFC Programming, Microsoft Visual C++
Tags: Visual C++ 6.0 MFC
Sign Up Now!
Solution Provided By: wayside
Participating Experts: 2
Solution Grade: A
 
 
[+][-]10.14.2008 at 10:48AM PDT, ID: 22713835

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 10:50AM PDT, ID: 22713853

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 10:55AM PDT, ID: 22713910

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 10:56AM PDT, ID: 22713913

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 10:59AM PDT, ID: 22713953

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 11:02AM PDT, ID: 22713995

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.14.2008 at 11:26AM PDT, ID: 22714210

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
 
Loading Advertisement...
20081119-EE-VQP-49 - Hierarchy / EE_QW_2_20070628